The volume (in litres) of hydrogen gas at 273 K and 1 atm pressure that will be consumed in obtaining 21.6 g of elemental boron (atomic mass =10.8 amu) from reduction of boron trichloride by hydrogen gas is : (as nearest integer)
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Solution
The reduction reaction of boron trichloride by hydrogen is as follows:
2BCl3+3H2→2B+6HCl
Mass of 2 moles of B=10.8×2=21.6 g
According to equation given above:
3 moles of H2 gas at STP reacts with BCl3 to give 21.6 g of boron.
Now, 1 mole of H2 at STP occupies a volume of 22.4 L.