Question

The volume (in mL) of $0.1M$ $AgN{O}_3$ for complete precipitation of chloride ions present in $30$ mL of $0.01M$ solution of $\left[Cr\right(H_{2}O{)}_{5}Cl]C{l}_2$ as silver chlorides is close to :

• A. $12$
• B. $5$
• C. $6$
• D. $3$

Answer 1

The correct option is C $6$

$30$ mL of $0.01M$ $\left[Cr\right(H_{2}O{)}_{5}Cl]C{l}_2=2C{l}^{⊝}$ ions

$\therefore$ Number of $C{l}^{⊝}$ ions $=30\times 0.01\times 2=0.6$ mmol

$\therefore$ Millimoles of $A{g}^{⨁}$ ions required $=0.6$ mmol

$V\times 0.1=0.6$ $\Rightarrow V=6$ mL