$0.1 N NaOH$ is required to neutralize $10 mL$ , $0.1 N$ of Phosphonic Acid. Calculate its volume (in mL).

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Solution

Step 1:
$H_{3} {PO}_{3} (l) + NaOH (aq) \to {NaH}_{2} {PO}_{2} (s) + H_{2} O (aq) Phosphonic Sodium Sodium Water Acid Hydroxide Hypophosphite$
Step 2:
For dilution or neutralization= $N_{1} V_{NaOH} = N_{2} V_{H_{3} {PO}_{2}}$
Putting values in the above expression:
$\begin{array}{rcl} 0.1 \times V_{NaOH} & = & 0.1 \times 10 \\ V_{NaOH} & = & \frac{0.1 \times 10}{0.1} \\ V_{NaOH} & = & 10 mL \end{array}$
Therefore, $10 mL$ is the volume of (Sodium Hydroxide) $NaOH$

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0.1NNaOH is required to neutralize 10mL,0.1N of Phosphonic Acid. Calculate its volume (in mL).

Step 1:H3PO3(l)+NaOH(aq)→NaH2PO2(s)+H2O(aq)PhosphonicSodiumSodiumWaterAcidHydroxideHypophosphiteStep 2:For dilution or neutralization=N1VNaOH=N2VH3PO2Putting values in the above expression:0.1×VNaOH=0.1×10VNaOH=0.1×100.1VNaOH=10mLTherefore,10mL is the volume of (Sodium Hydroxide)NaOH

$0.1 N NaOH$ is required to neutralize $10 mL$ , $0.1 N$ of Phosphonic Acid. Calculate its volume (in mL).