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Coordination and Oxidation Number

The volume in...

Question

The volume (in mL) of 1.0 M $A g N O_{3}$ required for the complete precipitation of chloride ions present in 30 mL of 0.01M solution of $[C r (H_{2} O)_{6}] C l_{3}$ , as silver chloride is:

0.9

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1.8

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Solution

The correct option is A 0.9
$[C r (H_{2} O)_{6}] C l_{3} + 3 A g N O_{3} \to [C r (H_{2} O)_{6}] (N O_{3})_{3} + 3 A g C l$
Because $[C r (H_{2} O)_{6}] C l_{3}$ has 3 ionisable $C l^{-}$ ions.
We know that, $M_{1} V_{1} = M_{2} V_{2}$
$M_{1} a n d M_{2}, V_{1} a n d V_{2}$ are concentration and volume of $[C r (H_{2} O)_{6}] C l_{3} a n d A g N O_{3} r e s p e c t i v e l y .$

Millimoles of $C l^{-}$ = 30 x 0.01 M x 3 = 0.9 M
So, volume of $A g^{+}$ required =0.9 x 1 = 0.9 mL

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