The volume occupied by 0.50 mole of propane gas, C3H8 at a temperature of 27oC and a pressure of 2.0 atmospheres is best expressed by which of the following? (R=0.082 liter-atom / moleo K)
A
0.50×0.082×272 liters
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B
0.50×0.082×3002 liters
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C
0.50×0.082×273300 liters
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D
0.50×0.082×3002×760 liters
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E
0.50×0.082×272×760 liters
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Solution
The correct option is A0.50×0.082×3002 liters Pressure P is 2 atm, the number of moles n is 0.50, the ideal gas constant R is 0.082 L atm / mol K and temperature T is 27oC or 27+273=300 K. Volume V =nRTP=0.50×0.082×3002 liters. Hence, option (B) is the correct answer.