Question

The volume occupied by 0.50 mole of propane gas, $C_3{H}_8$ at a temperature of ${27}^{o}C$ and a pressure of 2.0 atmospheres is best expressed by which of the following? (R=0.082 liter-atom / mole${}^o$ K)

• A. $\frac{0.50\times 0.082\times 27}{2}$ liters
• B. $\frac{0.50\times 0.082\times 300}{2}$ liters
• C. $\frac{0.50\times 0.082\times 273}{300}$ liters
• D. $\frac{0.50\times 0.082\times 300}{2\times 760}$ liters
• E. $\frac{0.50\times 0.082\times 27}{2\times 760}$ liters

Answer 1

Answer: (B)

$\frac{0.50\times 0.082\times 300}{2}$ liters

Pressure P is 2 atm, the number of moles n is 0.50, the ideal gas constant R is 0.082 L atm / mol K and temperature T is ${27}^{o}C$ or $27+273=300$ K.
Volume V $=\frac{nRT}{P}=\frac{0.50\times 0.082\times 300}{2}$ liters.
Hence, option (B) is the correct answer.