The volume occupied by 10 g of Oxygen at 0- C and 2 atm pressure will be approximately-A- 20 LB- 4-48 LC- 3-5 LD- 1-5 L

The correct option is C 3.5 L Given, Pressure = 2 atm Mass = 10 g Temperature = nbsp;0^o C Ideal gas equation is PV = nRT The value of R = 0.082 L atm mol^ 1 ...

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Cubical Expansion

The volume oc...

Question

The volume occupied by $10 g$ of Oxygen at $0^{o} C$ and 2 atm pressure will be approximately______.

20 L

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4.48 L

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3.5 L

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1.5 L

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Solution

The correct option is C
3.5 L

Given,
Pressure = 2 atm
Mass = 10 g
Temperature = $0^{o} C$
Ideal gas equation is $P V = n R T$
The value of R = $0.082 L a t m m o l^{- 1} K^{- 1}$

$V = \frac{n R T}{P} = \frac{10 \times .082 \times 273}{2 \times 32}$
$V = 3.49 ≅ 3.5 L$ .

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The volume occupied by 10 g of Oxygen at 0o C and 2 atm pressure will be approximately______.

The correct option is C 3.5 L Given, Pressure = 2 atm Mass = 10 g Temperature = 0o C Ideal gas equation is PV = nRT The value of R = 0.082 L atm mol−1 K−1 V=nRTP=10×.082×2732×32 V=3.49≅3.5L.

The volume occupied by $10 g$ of Oxygen at $0^{o} C$ and 2 atm pressure will be approximately______.

The correct option is C
3.5 L

Given,
Pressure = 2 atm
Mass = 10 g
Temperature = $0^{o} C$
Ideal gas equation is $P V = n R T$
The value of R = $0.082 L a t m m o l^{- 1} K^{- 1}$

$V = \frac{n R T}{P} = \frac{10 \times .082 \times 273}{2 \times 32}$
$V = 3.49 ≅ 3.5 L$ .