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Ideal Gas Equation

The volume oc...

Question

The volume occupied by $3.5$ g of $O_{2}$ gas at $27^{o} C$ & $760$ mm pressure is:

[Molecular weight of oxygen $= 16$ g/mole]

2.45

litres

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5.24

litres

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6.4

litres

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3.5

litres

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Solution

The correct option is C $2.45$ litres
As we know, one mole of a gaseous substance occupies $22.4$ litres

So, $32$ g of oxygen occupies $22.4$ litres

$∴$ $3.5$ g of oxygen occupies $3.5 \times \frac{22.4}{32} = 2.45$ litres

Hence, the correct answer is option $A$ .

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Similar questions

Q. 16 g of oxygen and 3 g of hydrogen are mixed and kept at 760 mm pressure and 0$$. The total volume occupied by the mixture will be nearly
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(D) 44800 ml

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The volume occupied by 3.5 g of O2 gas at 27oC & 760 mm pressure is:[Molecular weight of oxygen =16 g/mole]

The correct option is C 2.45 litresAs we know, one mole of a gaseous substance occupies 22.4 litres So, 32 g of oxygen occupies 22.4 litres ∴ 3.5 g of oxygen occupies 3.5×22.432=2.45 litresHence, the correct answer is option A.

The volume occupied by $3.5$ g of $O_{2}$ gas at $27^{o} C$ & $760$ mm pressure is:

[Molecular weight of oxygen $= 16$ g/mole]

The correct option is C $2.45$ litres
As we know, one mole of a gaseous substance occupies $22.4$ litres

So, $32$ g of oxygen occupies $22.4$ litres

$∴$ $3.5$ g of oxygen occupies $3.5 \times \frac{22.4}{32} = 2.45$ litres

Hence, the correct answer is option $A$ .