The volume occupied by 53.5 gm of $C l_{2}$ [Cl=35.5]

22.4 litre

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11.2 litre

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11.984 litre

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16.87 litre

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Solution

The correct option is D 16.87 litre
As we know, one mole of a gaseous substance occupies 22.4 liter. So, volume occupied by 53.5 g. of $C l_{2} = 53.5 \times \frac{22.4}{71} = 16.87 l i t e r$

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