Question

The volume occupied by $7.23\times {10}^{23}$ molecules of carbon dioxide and $3.01\times {10}^{23}$ molecules of argon by atom at $0^{\circ }\text{C}$ and $1\text{atm}$ pressure is___

• A. $38\text{mL}$
• B. $3.80\text{mL}$
• C. $3.8\times {10}^4\text{mL}$
• D. $3.8\times {10}^3\text{mL}$

Answer 1

The correct option is C $3.8\times {10}^4\text{mL}$

$7.23\times {10}^{23}$ molecules of $C{O}_2=\frac{7.23\times {10}^{23}}{6.023\times {10}^{23}}\text{mol}=1.2\text{mol}$

$3.01\times {10}^{23}$ atoms of $Ar=\frac{3.01\times {10}^{23}}{6.023\times {10}^{23}}\text{mol}=0.5\text{mol}$
Total moles = 1.7
Volume occupied at STP = $1.7\times 22.4\text{L}$
$=38.08\text{L}$
$=3.8\times {10}^4\text{mL}$