The volume occupied by 7 grams of nitrogen gas at STP is:

5.6 l

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11.2 l

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22.4 l

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44.8 l

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Solution

The correct option is A 5.6 l
No of mole of nitrogen $= \frac{7}{28} = \frac{1}{4}$ mole
As we know, one mole occupies 22.4 litre volume, so $\frac{1}{4}$ mole will occupy, $V = \frac{22.4}{4} = 5.6 l i t r e$ .

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