The volume occupied by a certain gas was found 5.6 ${dm}^{3}$ when the pressure was 2 atmosphere. If the pressure is increased by 20%, find the new volume of the gas.

Open in App

Solution

$Initial volume of gas V_{1} = 5.6 {dm}^{3} Initial pressure of gas P_{1} = 2 atm The 20 % of initial pressure = 2 x \frac{20}{100} = \frac{4}{10} = 0.4 Final pressure P_{2} = 0.4 + 2 = 2.4 atm Final volume V_{2} = ? P_{1} V_{1} = P_{2} V_{2} 2 x 5.6 = 2.4 x V_{2} V_{2} = \frac{5.6 x 2}{2.4} = 4.67 {dm}^{3}$

Suggest Corrections

Similar questions

The volume of a certain mass of a gas was found to be 800 cc when pressure was 760 mm of Hg. If the pressure increases by 50%. Calculate the new volume of the gas, assuming that temperature remains constant.

The volume occupied by a certain gas was found 7.6dm3 when the pressure was 8atm.If the pressure is increased by 20%.Find the new volume of tje gas

Q. The volume of certain gas was found to be

400 c m^{3}

when pressure was

520 m m H g

. If the pressure

P_{r}

is increased by

30

%, find the new volume of the gas.

Q. The volume of certain gas was found 400

{cm}^{3}

, when pressure was 520 mm of Hg. If the pressure is increased by 30%, find the new volume of the gas.

Q. The volume of a certain gas at constant temperature was found to be

1200 c m^{3}

when pressure is

1000 m m

H g

. If the pressure is decreased by

30 %

, find the new volume.

Join BYJU'S Learning Program

The volume occupied by a certain gas was found 5.6 dm3 when the pressure was 2 atmosphere. If the pressure is increased by 20%, find the new volume of the gas.

Initial volume of gas V1=5.6 dm3Initial pressure of gas P1 =2 atm The 20% of initial pressure = 2 x 20100 = 410 = 0.4 Final pressure P2=0.4 + 2 = 2.4 atm Final volume V2=? P1V1=P2V2 2 x 5.6=2.4 x V2 V2=5.6 x 2 2.4 = 4.67 dm3

The volume occupied by a certain gas was found 5.6 ${dm}^{3}$ when the pressure was 2 atmosphere. If the pressure is increased by 20%, find the new volume of the gas.