The volume occupied by an atom is greater then the volume of the nucleus by a factor of about

10^{1}

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10^{5}

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10^{10}

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10^{15}

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Solution

The correct option is D $10^{15}$
$V \propto r^{3}$
$V_{a t o m} = \frac{r_{a t o m}^{3}}{r_{n u c l e u s}^{3}} \times V_{n u l e u s}$
But, $= \frac{r_{n u c l e u s}}{r_{a t o m}} = {(\frac{1}{10^{5}})}^{3}$
Hence, $V_{a t o m} = 10^{15} \times V_{n u l e u s}$

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The volume occupied by an atom is greater then the volume of the nucleus by a factor of about

The correct option is D 1015V∝r3Vatom=r3atomr3nucleus×VnuleusBut, =rnucleusratom=(1105)3Hence, Vatom=1015×Vnuleus

The correct option is D $10^{15}$
$V \propto r^{3}$
$V_{a t o m} = \frac{r_{a t o m}^{3}}{r_{n u c l e u s}^{3}} \times V_{n u l e u s}$
But, $= \frac{r_{n u c l e u s}}{r_{a t o m}} = {(\frac{1}{10^{5}})}^{3}$
Hence, $V_{a t o m} = 10^{15} \times V_{n u l e u s}$