The volume occupied by half a mole of a gas at STP is.

5.6 L

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11.2 L

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22.4 L

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44.8 L

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Solution

The correct option is B 11.2 L
At STP volume occupied by 1 mole of a gas is 22.4 L.
At same conditions volume occupied by half mole of a gas is 11.2 L.
$V \propto n \frac{V_{1}}{V_{2}} = \frac{n_{1}}{n_{2}} V_{1} = 22.4 L, n_{1} = 1, n_{2} = \frac{1}{2} = 0.5 \frac{22.4}{V_{2}} = \frac{1}{0.5} ∴ V_{2} = 11.2 L$

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The volume occupied by half a mole of a gas at STP is.

The correct option is B 11.2 LAt STP volume occupied by 1 mole of a gas is 22.4 L.At same conditions volume occupied by half mole of a gas is 11.2 L.V∝nV1V2=n1n2V1=22.4L,n1=1,n2=12=0.522.4V2=10.5∴V2=11.2L