Question

The volume of $0.1N$ dibasic acid sufficient to neutralize $1g$ of a base that furnishes $0.04$ mole of ${OH}^{\overline{}}$ in aqueous solution is:

• A. $400ml$
• B. $600ml$
• C. $200ml$
• D. $80ml$

Answer 1

The correct option is A $400ml$

For ${OH}^{-}$, moles $=\frac{mass}{M}$

$\therefore 0.04=\frac{m}{17}$

$\therefore m=0.68g-\left(i\right)$

Now, $N_1{V}_1=N_2{V}_2$

$\therefore N_1{V}_1=\frac{mass}{eq.mass}$

$\therefore 0.1\times V_1=\frac{0.68}{17}$

$\therefore V_1=0.4l$

$\therefore V_1=400ml$