The volume of $1.5 g m$ atoms of helium gas under standard conditions of temperature and pressure is ___ liter.

33.6

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6.022

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9.033

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22.4

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Solution

The correct option is A 33.6

Volume of $1 g r a m$ atom of Helium = $22.4 L$ at STP

Volume of $1.5 g r a m$ atom of Helium = $1.5 \times 22.4 = 33.6 L$

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Similar questions

The volume of $1.5 g m$ atoms of helium gas under standard conditions of temperature and pressure is

The volume of $1.5 g m$ atoms of helium gas under standard conditions of temperature and pressure is ___ L.

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The total volume of mixture of 2 g of helium and 7 g of nitrogen under S.T.P. conditions is

22.4 L

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