The volume of $1.5 g m$ atoms of helium gas under standard conditions of temperature and pressure is

22.4 lit

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33.6 lit

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44.8 lit

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11.2 lit

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Solution

The correct option is B
33.6 lit

Volume of $1 g r a m$ atom of Helium = $22.4 L$

Volume of $1.5 g r a m$ atom of Helium = $1.5 \times 22.4 = 33.6 L$

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