The volume of $1.5 M$ $H_{3} P O_{4}$ solution required to neutralize exactly $90$ mL of a $0.5$ M $B a (O H)_{2}$ solution is:

10

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30

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20

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60

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Solution

The correct option is C $20$ mL
$20$ mL of solution is required to neutralize exactly $90$ mL of a $0.5$ M $B a (O H)_{2}$ solution.

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