Question

The volume of 1.5 M ${\text{H}}_{\text{2}}\text{S}{\text{O}}_4$ required to completely neutralize 150 mL of 2 M NaOH solution is

• A. 150 mL
• B. 200 mL
• C. 100 mL
• D. 250 mL

Answer 1

Answer: (B)

200 mL

${\text{M}}_{\text{1}}{\text{V}}_{\text{1}}={\text{M}}_{\text{2}}{\text{V}}_{\text{2}}$

1 represents $H_{2}S{O}_4$ and 2 represents $NaOH$

$1.5\times {\text{V}}_1=2\times 150$

${\text{V}}_1=\frac{2\times 150\times 10}{15}$ = 200 mL