Question

The volume of 1 mole of oxygen gas is 22400 mL at 760 mm. Calculate the temperature of the gas(Given $R=0.082L-atmmo{l}^{-1}K-1$)

• A. ${273.17}^{\circ }C$
• B. ${273}^{\circ }C$
• C. ${1.17}^{\circ }C$
• D. ${0.17}^{\circ }C$

Answer 1

The correct option is D

${0.17}^{\circ }C$

We know from the ideal gas equation for 1 mole of ideal gas,

$PV=RT;orT=\frac{PV}{R}$

where $P=760mm=1atm$

$V=22400mL=22.4L$

$R=0.082Latmmo{l}^{-1}K-1$

$\Rightarrow T=\frac{1\times 22.4}{0.082}\Rightarrow T=273.17K$

Temperature in Celsius Scale $=(273.17-273)={0.17}^{\circ }C$