The volume of 10 N and 4N HCI required to make 1 L of 7 N HCL are
A
0.5 L of 10 N HCI and 0.5 L of 4N HCI
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B
0.6L of 10 N HCI of 0.4 L of 4N HCI
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C
0.8 L of 10 N HCI & 0.2 L of 4 N HCI
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D
0.75 L of 10 N HCI of 0.25 L of 4N HCI
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Solution
The correct option is A0.5 L of 10 N HCI and 0.5 L of 4N HCI N1V1+N2V2=NV Where V1+V2=1L Or V2=(1−V1)L 10×V1+4(1−V1)=1×7 10V1+4−4V1=7 6V1=3 V1=36=0.5L V2=0.5L