The volume of $22 g$ moles of $C O_{2}$ gas at $N T P$ is equal to:

11.2 l i t e r s

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22.4 l i t e r s

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44.8 l i t e r s

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none of these

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Solution

The correct option is D none of these
$22 g o f {C O}_{2} i s h a l f a m o l e o f {C O}_{2} (44 g / m o l)$

$P V = n R T$
$W h e r e, n = \frac{m}{M}$
$V = \frac{m R T}{P M}$
$V = \frac{22 g \times 0.0821 L a t m / m o l K \times 293 K}{1 a t m \times 44.0 g / m o l}$
$V = 12 L$

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