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Byju's Answer
Standard XII
Chemistry
Faraday's First Law
The volume of...
Question
The volume of 3M HNO3 required to oxidise 8g Fe2+ is
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Q.
The volume (ml) of 3M
H
N
O
3
required to oxidised 8 g
F
e
2
+
is:
(
H
N
O
3
+
F
e
2
+
→
F
e
3
+
+
N
O
+
H
2
O
)
:
Q.
Volume of
0.02
M
M
n
O
4
−
solution required to oxidise
40.0
mL of
0.1
M
F
e
2
+
solution is
:
Q.
The volume of
H
N
O
3
(having specific gravity of
1.05
g
/
m
L
containing
8
%
by mass of
H
N
O
3
) required to oxidize iron in
1
g
F
e
S
O
4
⋅
7
H
2
O
in acid medium as
F
e
2
+
+
H
N
O
3
+
H
+
⟶
F
e
3
+
+
N
O
+
H
2
O
is
x
×
10
−
1
. The value of
x
is :
Q.
What volume of
3
M
H
N
O
3
is needed to oxidize
8
g of
F
e
2
+
to
F
e
3
+
?
H
N
O
3
gets converted to
N
O
.
Q.
If equal volumes of
0.1
M
K
M
n
O
4
and
0.1
M
K
2
C
r
2
O
7
solutions are allowed to oxidise
F
e
2
+
t
o
F
e
3
+
in acidic medium, then
F
e
2
+
oxidised will be :
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