The volume of 8 $g$ of hydrogen gas is .... $c m^{3}$ at $S T P$ .

67200

No worries! We‘ve got your back. Try BYJU‘S free classes today!

56000

No worries! We‘ve got your back. Try BYJU‘S free classes today!

89600

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

78400

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C 89600
Volume of 2 $g$ of $H_{2}$ gas at $S T P$ = 22400 $c m^{3}$
Volume of 8 $g$ of $H_{2}$ gas at $S T P$ = $\frac{22400}{2} \times 8$ = 89600 $c m^{3}$

Suggest Corrections

Similar questions

Q. If 1 mL of Hydrogen gas reacts with 1 mL of chlorine gas at STP, the volume of hydrogen chloride gas produced at STP is:

12g of me on the reacting with acid gives hydrogen gas the volume of which at stp is

Q. Assertion :20 g of argon (atomic mass of

A r = 40

) occupies volume of 22400

c m^{3}

at STP. Reason: 4 g of helium (atomic mass of

H e = 4

) occupies a volume of 22400

c m^{3}

at STP.

Q. Calculate the volume of ammonia gas produced at STP when 140 g of nitrogen gas reacts with 30 g hydrogen gas.

(Atomic mass:

N = 14 u, H = 1 u

)

Hydrogen gas is prepared in the laboratory by reacting dilute HCl with granulated zinc. Following reaction takes place

$Z n + 2 H C l \to Z n C l_{2} + H_{2}$

Calculate the volume of hydrogen gas liberated at STP when 32.65 g of zinc reacts with HCl. 1 mol of a gas occupies 22.7 L volume at STP; atomic mass of Zn = 65.3u

Join BYJU'S Learning Program

The volume of 8 g of hydrogen gas is .... cm3 at STP.

The correct option is C 89600Volume of 2 g of H2 gas at STP = 22400 cm3Volume of 8 g of H2 gas at STP = 224002×8 = 89600 cm3

The volume of 8 $g$ of hydrogen gas is .... $c m^{3}$ at $S T P$ .

The correct option is C 89600
Volume of 2 $g$ of $H_{2}$ gas at $S T P$ = 22400 $c m^{3}$
Volume of 8 $g$ of $H_{2}$ gas at $S T P$ = $\frac{22400}{2} \times 8$ = 89600 $c m^{3}$