The volume of $8$ g of $O_{2}$ at STP is:

22.4

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11.2

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5.6

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2.24

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Solution

The correct option is C $5.6$ L
Number of moles of $O_{2} = \frac{8}{32} = \frac{1}{4} = 0.25$

Volume of 1 mol of $O_{2}$ at STP $= 22.4$ L

$∴$ Volume of 0.25 mol of $O_{2}$ at STP $= 22.4 \times 0.25 = 5.6$ L

Hence, the correct option is $C$

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