The volume of a 490 g sealed packet is 280 cm $^{3}$ -. Will the packet float or sink in water? The density of water is 1 g/cm $^{3}$

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Solution

Density of sealed packet = $\frac{M a s s}{V o l u m e} = 1.75 g m / c m^{3}$ .
Since density of sealed packet is more than density of water ,it will sink in water .

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The volume of a 490 g sealed packet is 280 cm3-. Will the packet float or sink in water? The density of water is 1 g/cm3

Density of sealed packet = MassVolume=1.75gm/cm3 .Since density of sealed packet is more than density of water ,it will sink in water .

The volume of a 490 g sealed packet is 280 cm $^{3}$ -. Will the packet float or sink in water? The density of water is 1 g/cm $^{3}$

Density of sealed packet = $\frac{M a s s}{V o l u m e} = 1.75 g m / c m^{3}$ .
Since density of sealed packet is more than density of water ,it will sink in water .