The volume of a circular iron rod of length 1 m is 3850 cm³. Find its diameter.

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Solution

Volume $= {πr}^{2} h = 3850 {cm}^{3}$
Height = 1 m =100 cm

Now, radius, $r = \sqrt{\frac{3850}{π \times h}} = \sqrt{\frac{3850 \times 7}{22 \times 100}} = 1.75 \times 7 = 3.5 c m$
∴ Diameter =2(radius) $= 2 \times 3.5 = 7 c m$

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