Question

The volume of a cube is $512c{m}^3$ .Its total surface area is

$\left(a\right)256c{m}^2$

$\left(b\right)384c{m}^2$

$\left(c\right)512c{m}^2$

$\left(d\right)64c{m}^2$

Answer 1

The volume of a cube of side "$a$" is $a^3$

It is given that,

The volume of the cube $=512c{m}^3$

$\Rightarrow a^3=512c{m}^3$

$\Rightarrow a^3=(8cm{)}^3$

$\Rightarrow a=8cm$

Total surface area of the cube $=6a^2$

$=6\times (8cm{)}^2$

$=6\times 64c{m}^2$

$=384c{m}^2$

Hence, Option B is correct.