The volume of a cube is $2.5 {c m}^{3}$ and its mass is 20g. Calculate the density of the cube in MKS and CGS systems.

0.008 g / {c m}^{3} a n d 8 k g / m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8000 g / {c m}^{3} a n d 8 k g / m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

8 g / {c m}^{3} a n d 8000 k g / m^{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.8 g / {c m}^{3} a n d 800 k g / m^{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $8 g / {c m}^{3} a n d 8000 k g / m^{3}$
Explanation: In MKS system i.e. the SI system the unit of density is $k g / m^{3}$ and in CGS system it is $g / {c m}^{3}$ . Density = mass/volume = $20 / 2.5 = 8 g / {c m}^{3}$ in CGS system. In MKS system density = $8 \times 1000 = 8000 k g / m^{3}$

Suggest Corrections

m^{3}

m^{3}

l = 1.2 \times 10^{- 2}

m^{3}

614.125

m^{3}

13

m^{3}

Join BYJU'S Learning Program