Question

The volume of a cube of side $\frac{9}{2}$ cm in different forms is ______.

• A. $\frac{729}{8}c{m}^3$
• B. $\frac{729}{27}c{m}^3$
• C. $\frac{343}{27}c{m}^3$
• D. 91.125 $c{m}^3$

Answer 1

Answer: (A), (D)

91.125 $c{m}^3$

Volume of a cube of side 's' cm is $s^{3}c{m}^3$.
Therefore for a cube of side $\frac{9}{2}$ cm,
the volume is = $(\frac{9}{2}{)}^3$
$=\frac{9}{2}\times \frac{9}{2}\times \frac{9}{2}$

$=\frac{9\times 9\times 9}{2\times 2\times 2}$

$=\frac{729}{8}c{m}^3$

$=91.125c{m}^3$