Question

The volume of a cube of side $\frac{9}{2}$ cm is ______.

• A. $\frac{729}{8}c{m}^3$
• B. $\frac{343}{27}c{m}^3$
• C. 91.125 $c{m}^3$
• D. $\frac{729}{27}c{m}^3$

Answer 1

Answer: (A), (C)

The correct options are
A

$\frac{729}{8}c{m}^3$

C

91.125 $c{m}^3$

Volume of a cube of side 's' cm is $s^{3}cm$.
Therefore for a cube of side $\frac{9}{2}$ cm, the volume is = $(\frac{9}{2}{)}^3$ = $\frac{9}{2}\times \frac{9}{2}\times \frac{9}{2}=\frac{9\times 9\times 9}{2\times 2\times 2}=\frac{729}{8}c{m}^3=91.125c{m}^3$