The volume of a cuboid is $6400 c u c m$ . Its length is $32 c m$ , and breadth and height are in the ratio $2 : 1$ . Find its breadth and height.

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Solution

Let $2 x$ and $x$ be the breadth and height of the cuboid.
Length of cuboid $(l) = 32 c m$
As we know that,
Volume of cuboid $= l \times b \times h = 6400 {c m}^{3} (Given)$
$∴ 32 \times 2 x \times x = 6400$
$64 x^{2} = 6400$
$\Rightarrow x = \sqrt{\frac{6400}{64}} = 10 c m$
Therefore,
Breadth of cuboid $= 2 \times 10 = 20 c m$
Height of the cuboid $= x = 10 c m$

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The volume of a cuboid is 6400 cu cm. Its length is 32 cm, and breadth and height are in the ratio 2:1. Find its breadth and height.

Let 2x and x be the breadth and height of the cuboid.Length of cuboid (l)=32cmAs we know that,Volume of cuboid =l×b×h=6400cm3(Given)∴32×2x×x=640064x2=6400⇒x=√640064=10cmTherefore,Breadth of cuboid =2×10=20cmHeight of the cuboid =x=10cm

The volume of a cuboid is $6400 c u c m$ . Its length is $32 c m$ , and breadth and height are in the ratio $2 : 1$ . Find its breadth and height.