Let p(x) = x3 + 13x2 + 32x + 20
Put x = (−1) in p(x)
p(−1) = (−1)3 + 13(−1)2 + 32(−1) + 20
= (−1) + 13(1) − 32 + 20
= −33 + 33 = 0
Hence (x + 1) is a factor of p(x)
On dividing, p(x) with (x + 1) we get
p(x) = (x + 1)(x2 + 12x + 20)
= (x + 1)(x2 + 10x + 2x + 20)
= (x + 1)[x(x + 10) + 2(x + 10)]
= (x + 1)(x + 10)(x + 2)
Volume of cuboid = l × b × h = (x + 1)(x + 10)(x + 2)
Hence the dimensions of the cuboid are (x + 1), (x + 10) and (x + 2)