Question

# The volume of a cuboidal box is 48 cm3. If its height and length are 3 cm and 4 cm respectively, find its breadth.

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Solution

## $\mathrm{Suppose}\mathrm{that}\mathrm{the}\mathrm{breadth}\mathrm{of}\mathrm{the}\mathrm{box}\mathrm{is}b\mathrm{cm}.\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathrm{Volume}\mathrm{of}\mathrm{the}\mathrm{cuboidal}\mathrm{box}=48{\mathrm{cm}}^{3}\phantom{\rule{0ex}{0ex}}\mathrm{Height}\mathrm{of}\mathrm{the}\mathrm{box}=3\mathrm{cm}\phantom{\rule{0ex}{0ex}}\mathrm{Length}\mathrm{of}\mathrm{the}\mathrm{box}=4\mathrm{cm}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}\mathrm{Now},\mathrm{volume}\mathrm{of}\mathrm{box}=\mathrm{length}×\mathrm{breadth}×\mathrm{height}\phantom{\rule{0ex}{0ex}}⇒48=4×b×3\phantom{\rule{0ex}{0ex}}⇒48=12×b\phantom{\rule{0ex}{0ex}}⇒b=\frac{48}{12}=4\mathrm{cm}\phantom{\rule{0ex}{0ex}}\therefore \mathrm{The}\mathrm{breadth}\mathrm{of}\mathrm{the}\mathrm{cuboidal}\mathrm{box}\mathrm{is}4\mathrm{cm}.$

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