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Question

The volume of a cylinder is computed from measurements of its height (h) and diameter (d). A set of several measurements of height has an average value of 0.2 m and a standard deviation of 1%. The average value obtained for the diameter is 0.1 m and the standard deviation is 1%. Assuming the errors in the measurements of height and diameter are uncorrelated, the standard deviation of the computed volume is

A
1.00%
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B
1.73%
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C
2.23%
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D
2.41%
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Solution

The correct option is C 2.23%
Volume of cylinder,

V=πr2 h

Vr=2πrh

Vh=πr2

Given, h = 0.2 m and d = 0.1 m

r=0.05 m; σr=1100×0.05=5×104

σh=0.2×1100=2×103

Standard deviation of volume,

σh=0.2×1100=2×103

σv=(2πrh)2.(5×104)2+(πr2)2(2×103)2

σv=3.512×104

% σv=3.5×104π×(0.05)2×0.2×100% =2.23%

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