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Question

The volume of a drop of water is 0.05 mL and the density of water is 1.0 g/mL. How many water molecules are present in a drop of water?

A
1.7×1021
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B
5.4×1023
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C
2.2×1026
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D
1.71×1020
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Solution

The correct option is A 1.7×1021
As, Density=massvolume
So, mass=1.0 g/ml×0.05 mL=0.05 g
Using Avogadro's law, 18 g of H2O contains 6.023×1023 molecules.
So, 0.05 g of H2O contains =6.023×102318×0.05=1.67×1021 molecules.

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