The volume of a drop of water is 0.05mL and the density of water is 1.0g/mL. How many water molecules are present in a drop of water?
A
1.7×1021
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B
5.4×1023
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C
2.2×1026
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D
1.71×1020
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Solution
The correct option is A1.7×1021 As, Density=massvolume So, mass=1.0g/ml×0.05mL=0.05g Using Avogadro's law, 18g of H2O contains 6.023×1023 molecules. So, 0.05g of H2O contains =6.023×102318×0.05=1.67×1021 molecules.