The volume of a frustum cone is 4,200 cm3, whose base and upper area of a circle is 40 and 10 cm2. Find the height of the cone.
Volume of a frustum cone = 13(A1+A2+√A1A2)h
4,200 = 13(40+10+√40×10)×h
4,200 = 13(50+√400)×h
4,200 = 13(50+20)×h
4,200×3 = 70×h
h = 4,200 × 3/70
h = 180 cm