Question

The volume of a gas at 0${}^0$C is 546cc at constant pressure it is heated from 30${}^0$C to 50${}^0$C the change in volume is

• A. 60cc
• B. 40cc
• C. 10cc
• D. 273cc

Answer 1

Answer: (B)

40cc

According to Charle's Law, $V\propto T$

$\frac{V_0}{V_1}=\frac{T_0}{T_1}$
$\therefore \frac{546}{V_1}=\frac{0+273}{30+273}$ Temp is taken in Kelvin scale
$\therefore V_1=606cc$

$\frac{V_0}{V_2}=\frac{T_0}{T_2}$

$\therefore \frac{546}{V_2}=\frac{0+273}{50+273}$

$\therefore V_2=646cc$
$\Rightarrow V_2-V_1=646-606=40cc$