The volume of a gas at STP is 1.12×10−7cc. The number of molecules in it will be:
A
3.1×1020
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B
3.01×1012
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C
30.1×1013
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D
3.01×1024
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Solution
The correct option is B3.01×1012 Volume of 1 mole of gas at STP is 22.4L or 22400mL or 22400cc 22400mL of gas contains 6.023×1023 molecules 1.12×10−7cc contain 6.023×102322400×1.12×10−7 molecules =3.01×1012 molecules