The volume of a gas increases by 10 m3- when it is subjected to a constant pressure of 2 - 105 Pa- The amount of work done by the gas is

Given, Pressure applied (P)=2 × 10^5 Pa Change in volume (Δ V)=10 m^3 Work done by the gas, W=P ×Δ V=2 × 10^5 × 10 ⇒ W=2000 kJ ...

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Standard XII

Physics

Work

The volume of...

Question

The volume of a gas increases by $10 m^{3}$ , when it is subjected to a constant pressure of $2 \times 10^{5} Pa$ . The amount of work done by the gas is

500 kJ

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1000 kJ

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1500 kJ

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2000 kJ

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Solution

The correct option is D $2000 kJ$
Given,
Pressure applied $(P) = 2 \times 10^{5} Pa$
Change in volume $(Δ V) = 10 m^{3}$
Work done by the gas,
$W = P \times Δ V = 2 \times 10^{5} \times 10$
$\Rightarrow W = 2000 kJ$

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The volume of a gas increases by 10 m3, when it is subjected to a constant pressure of 2×105 Pa. The amount of work done by the gas is

The correct option is D 2000 kJGiven, Pressure applied (P)=2×105 Pa Change in volume (ΔV)=10 m3 Work done by the gas, W=P×ΔV=2×105×10 ⇒W=2000 kJ

The volume of a gas increases by $10 m^{3}$ , when it is subjected to a constant pressure of $2 \times 10^{5} Pa$ . The amount of work done by the gas is

The correct option is D $2000 kJ$
Given,
Pressure applied $(P) = 2 \times 10^{5} Pa$
Change in volume $(Δ V) = 10 m^{3}$
Work done by the gas,
$W = P \times Δ V = 2 \times 10^{5} \times 10$
$\Rightarrow W = 2000 kJ$