The volume of a gas is directly proportional to its absolute temperature. If the temperature of a gas is raised from $300 K$ to $600 K$ , and its volume at $300 K$ is $3.0 L$ , what is its volume at $600 K$ ?

1.5 L

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6.0 L

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303 L

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4.0 L

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12.0 L

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Solution

The correct option is B $6.0 L$
Given : $V_{1} = 3.0$ L ; $T_{1} = 300$ K ; $T_{2} = 600$ K
As $V \propto T$
$⟹ \frac{V_{2}}{V_{1}} = \frac{T_{2}}{T_{1}}$
$∴$ $\frac{V_{2}}{3.0} = \frac{600}{300}$
$⟹ V_{2} = 6.0$ $L$

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