The volume of a gas is reduced adiabatically to 1-3 rd of its orignal volume at 27- C- If Y -1-4- the new temperature of the gas will beA- 30020-4 KB- 30030-4 KC- 30021-4 KD- 30031-4 K

The correct option is B (300)(3)^0.4 KT_1 = 27^∘ C = 300 K For an adiabatic compression, T_1V_1^γ 1=T_2V_2^γ 1 300(V_1)^1.4 1=T_2(V_1/3)^1.4 1 T_2=300(3)^0.4 K ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Work Done

The volume of...

Question

The volume of a gas is reduced adiabatically to $\frac{1}{3}$ rd of its orignal volume at $27^{\circ}$ C. If $γ = 1.4$ , the new temperature of the gas will be

(300) (2)^{0.4}

K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(300) (3)^{0.4}

K

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(300) (2)^{1.4}

K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

(300) (3)^{1.4}

K

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B $(300) (3)^{0.4}$ $K$
$T_{1} = 27^{\circ} C$ = $300$ $K$
For an adiabatic compression,
$T_{1} {V_{1}}^{γ - 1} = T_{2} {V_{2}}^{γ - 1}$
$300 {(V_{1})}^{1.4 - 1} = T_{2} {(\frac{V_{1}}{3})}^{1.4 - 1}$
$T_{2} = 300 (3)^{0.4}$ $K$

Suggest Corrections

Similar questions

Q. The volume of a gas is reduced adiabatically to

\frac{1}{3}

rd of its orignal volume at

27^{\circ}

C. If

γ = 1.4

, the new temperature of the gas will be

Q. The volume of a gas is reduced adiabatically to

{\frac{1}{4}}^{t h}

of its orignal volume at

27^{\circ}

C. If

γ = 1.4

, the new temperature of the gas will be

Q. The volume of a gas is reduced adiabatically to

\frac{1}{4}

of its volume at

27^{o} C

. If

γ = 1.4

. The new temperature will be:

Q. The volume of a gas is reduced to

\frac{1}{4}

of its initial volume adiabatically at

27^{o}

. The final temperature of the gas (if

γ = 1.4

) will be

Q. The volume of a poly-atomic gas

(y = \frac{4}{3})

compressed adiabatically to

\frac{1}{8^{t h}}

of the orignal volume. if the orignal pressure of the gas is

p_{0}

the new pressure will be:

Join BYJU'S Learning Program

The volume of a gas is reduced adiabatically to 13rd of its orignal volume at 27∘C. If γ=1.4, the new temperature of the gas will be

The correct option is B (300)(3)0.4 KT1=27∘C = 300 K For an adiabatic compression, T1V1γ−1=T2V2γ−1 300(V1)1.4−1=T2(V13)1.4−1 T2=300(3)0.4 K

The volume of a gas is reduced adiabatically to $\frac{1}{3}$ rd of its orignal volume at $27^{\circ}$ C. If $γ = 1.4$ , the new temperature of the gas will be

The correct option is B $(300) (3)^{0.4}$ $K$
$T_{1} = 27^{\circ} C$ = $300$ $K$
For an adiabatic compression,
$T_{1} {V_{1}}^{γ - 1} = T_{2} {V_{2}}^{γ - 1}$
$300 {(V_{1})}^{1.4 - 1} = T_{2} {(\frac{V_{1}}{3})}^{1.4 - 1}$
$T_{2} = 300 (3)^{0.4}$ $K$