Question

The volume of a right circular cone of height 12 cm and base radius 6 cm,is

$\left(a\right)\left(2\pi \right)c{m}^3\left(b\right)\left(36\pi \right)c{m}^3\left(c\right)\left(72\pi \right)c{m}^3\left(d\right)\left(144\pi \right)c{m}^3$

Answer 1

ANSWER:
(d) $144\pi c{m}^3$
Volume of the cone = $\frac{1}{3}\pi r^{2}h$
= $\frac{1}{3}\pi \times 6^2\times 12=\pi \times 36\times 4=144\pi c{m}^3$