The volume of a right circular cylinder is $9856 c m^{3}$ . If the diameter of the base is $28 c m$ . find
height of the cylinder.

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Solution

$\begin{matrix} V o l u m e o f r i g h t c i r c u l a r c y l i n d e r = 9856 c m^{3} d i a m e t e r = 28 r a d i u s = 14 V o l u m e = π r^{2} h = 9856 = \frac{22}{7} \times 14 \times 14 \times h = 9856 h = \frac{9856 \times 7}{22 \times 14 \times 14} = 16 c m \end{matrix}$

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The volume of a right circular cylinder is 9856 cm3. If the diameter of the base is 28 cm. findheight of the cylinder.

Volumeofrightcircularcylinder=9856cm3diameter=28radius=14Volume=πr2h=9856=227×14×14×h=9856h=9856×722×14×14=16cm

The volume of a right circular cylinder is $9856 c m^{3}$ . If the diameter of the base is $28 c m$ . find
height of the cylinder.

$\begin{matrix} V o l u m e o f r i g h t c i r c u l a r c y l i n d e r = 9856 c m^{3} d i a m e t e r = 28 r a d i u s = 14 V o l u m e = π r^{2} h = 9856 = \frac{22}{7} \times 14 \times 14 \times h = 9856 h = \frac{9856 \times 7}{22 \times 14 \times 14} = 16 c m \end{matrix}$