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Boyle's Law

The volume of...

Question

The volume of a scuba tank is 10.0 L. It contains a mixture of nitrogen and oxygen at 290 atm. What volume of this mixture could the tank supply to a diver at 2.40 atm?

1509 L

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1209 L

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1238 L

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1338 L

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Solution

The correct option is B
1209 L

According to Boyle's law: $P_{1} V_{1} = P_{2} V_{2}$

Here $P_{1} = 290 a t m : P_{2} = 2.40 a t m : V_{1} = 10 L$

$\Rightarrow V_{2} = \frac{290 \times 10}{2.4}$

$\Rightarrow V_{2} = 1209 L$

Therefore, the volume of gas produced= 1209 L

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