Question

The volume of ammonia obtained by the combination of $10mL$ of $N_2$ and $30mL$ of $H_2$ is :

• A. $20mL$
• B. $40mL$
• C. $30mL$
• D. $10mL$

Answer 1

The correct option is A $20mL$

Given that

Volume of $N_2\left(V_{N_2}\right)=10ml$

Volume of $H_2\left(V_{H_2}\right)=30ml$

$\frac{V_{N_2}}{V_{H_2}}=\frac{10}{30}=\frac{1}{3}$

$\Rightarrow$ They are present in stiochiometric ratio.

Now,

$N_2+3H_2⟶2N{H}_3$

$V3V2V$

$10ml30ml⟶20ml$

$\therefore$ Volume of $N{H}_3$ produce $\left(V\right)=20ml$