The volume of an air bubble becomes three times as it rises from the bottom of a lake to its surface. Assuming atmospheric pressure to be 75 cm of Hg and the density of water to be 1/10 of the density of mercury, the depth of the lake is
15m
P1V1=P2V2⇒(P0+hρg)V=P0×3V
⇒hρg=2P0⇒h=2×75×13.6×g13.610×g=15 m