The volume of an object is 20 cm³ and the mass is 50 g. The density of water is 1 gm^-3. Will the object float on water or sink in water?

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Solution

$ρ = \frac{m a s s}{v o l u m e} ρ = \frac{50 g}{20 c . m^{3}} = 2.5 g / c . m^{3} I t i s g r e a t e r t h a n t h e d e n s i t y o f w a t e r . H e n c e, t h e o b j e c t w i l l sin k i n w a t e r .$

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The volume of an object is 20 cm3 and the mass is 50 g. The density of water is 1 gm-3. Will the object float on water or sink in water?

ρ = massvolumeρ = 50 g20 c.m3 = 2.5 g/c.m3It is greater than the density of water. Hence, the object will sink in water.

The volume of an object is 20 cm³ and the mass is 50 g. The density of water is 1 gm^-3. Will the object float on water or sink in water?

$ρ = \frac{m a s s}{v o l u m e} ρ = \frac{50 g}{20 c . m^{3}} = 2.5 g / c . m^{3} I t i s g r e a t e r t h a n t h e d e n s i t y o f w a t e r . H e n c e, t h e o b j e c t w i l l sin k i n w a t e r .$