The volume of certain gas was found 400 ${cm}^{3}$ , when pressure was 520 mm of Hg. If the pressure is increased by 30%, find the new volume of the gas.

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Solution

$Initial volume of gas V_{1} = 400 {cm}^{3} Initial pressure of gas P_{1} = 520 mm Hg The 30 % of initial pressure = 520 \times \frac{30}{100} = 156$

$Final pressure P_{2} = 156 + 520 = 676 mm Hg Final volume of gas V_{2} = ? P_{1} V_{1} = P_{2} V_{2} 520 \times 400 = 676 \times V_{2} V_{2} = \frac{520 \times 400}{676} = 307.69 {cm}^{3}$

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The volume of certain gas was found 400 cm3, when pressure was 520 mm of Hg. If the pressure is increased by 30%, find the new volume of the gas.

Initial volume of gas V1 = 400 cm3 Initial pressure of gas P1 = 520 mm Hg The 30% of initial pressure = 520 ×30100=156 Final pressure P2 = 156 + 520 = 676 mm Hg Final volume of gas V2 = ? P1V1= P2V2 520 ×400 = 676 ×V2 V2=520 × 400676 = 307.69 cm3

The volume of certain gas was found 400 ${cm}^{3}$ , when pressure was 520 mm of Hg. If the pressure is increased by 30%, find the new volume of the gas.