Question

The volume of decamolar aqueous solutions of hydrochloric acid is required to prepare ${2dm}^3$ of $5M$ $HCl$ solution is:

• A. $0.5L$
• B. $1L$
• C. $2L$
• D. $3L$

Answer 1

Answer: (B)

$1L$

We know,

$M_1{V}_1=M_2{V}_2$

$M_1=5M,V_1=2d{m}^3,M_2=10M$

$\therefore V_2=\frac{M_1{V}_1}{M_2}=\frac{5\times 2}{10}=1L$

$\therefore$ Volume required $=1L.$