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Question

The volume of ethyl alcohol (density 1.15 g/cc) that has to be added to prepare 100 cc of 0.5 M ethyl alcohol solution in water is :

A
1.15 cc
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B
2 cc
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C
2.15 cc
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D
2.30 cc
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Solution

The correct option is C 2 cc
Molarity =mass×1000molecularweight×volumeofsolution

Molecular weight of ethyl alcohol,
C2H5OH=12×2+5+16+1
=24+22=46 gmol1

On substituting the values, we get
0.5 M=mass×100046×100
Mass =0.5×4610=2.3 g

Volume of ethyl alcohol required,
V=massofethylalcoholdensityofethylalcohol=2.3 g1.15 g/cc=2 cc

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